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Daniel [21]
3 years ago
5

The distance between two cities on a map is 10 in. The actual distance between the cities is 135. What is the scale on the map?

Show all work for full credit!
Mathematics
1 answer:
spayn [35]3 years ago
4 0
The scale on the map is 1 in = 13.5 units


135/10 = 13.5
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Find the equation of the line that passes through the point left (-9,12) and is perpendicular to the line y=3/2x-1/2. Write the
ohaa [14]

Answer:

The answer to your question is: y = -2/3 x + 18

Step-by-step explanation:

Data

Point = (-9, 12)

line   y = 3/2x -1/2     perpendicular

Process

The line must be perpendicular to the line given. Then,

slope is the line given = 3/2, we change it because the lines must be perpendicular ,

New slope         M =  -2/3

New line       y-y1 = m(x - x1)

                     y - 12 = -2/3 (x + 9)             Substitution

                   3( y - 12) = -2(x + 9)

                   3y - 36 = -2x - 18                 Simplify

                   3y = -2x - 18 + 36

                   3y = -2x + 18

                      y = -2/3 x+ 18                      Result

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3 years ago
Which of the following ordered pairs is a solution of the given system of linear equations?
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B. I'm terrible at explaining but I'm sure that's right.
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A box of cereal weighs 12 ounces and costs $2.16. What is the price of the cereal per ounce?
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Read 2 more answers
A jar of peanut butter contains 454 g with a standard deviation of 10.2 g. Find the probability that a jar contains more than 46
Fofino [41]

Answer:

The probability that a jar contains more than 466 g is 0.119.

Step-by-step explanation:

We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.

Let X = <u><em>Amount of peanut butter in a jar</em></u>

The z-score probability distribution for the normal distribution is given by;

                                Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 454 g

           \sigma = standard deviation = 10.2 g

So, X ~ Normal(\mu=454 , \sigma^{2} = 10.2^{2})

Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)

            P(X > 466 g) = P( \frac{X-\mu}{\sigma} > \frac{466-454}{10.2} ) = P(Z > 1.18) = 1 - P(Z \leq 1.18)

                                                                  = 1 - 0.881 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

4 0
3 years ago
The tickets for a dance recital cost $5.00 for adults and $2.00 for children. If the total number of tickets sold was 295 and th
dem82 [27]
To solve, you would need to make two equations and substitute one in for the other. Let a = # of adults, and c = # of children

5a + 2c = 1,220
a + c = 295

a + c = 295
-c         -c
a = 295 - c

5(295 - c) + 2c = 1,220
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1,475 - 3c = 1,220

1,475 - 3c = 1,220
-1,475           -1,475
-3c = -255

-3c/-3 = -255/-3
c = 85

a + c = 295
a + 85 = 295
     -85    -85
a = 210

210 adults attended the dance recital

Hope this helps!
6 0
3 years ago
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