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svet-max [94.6K]
4 years ago
5

a rectangle has a length of x inches and a width 3 inches less than the length. if the dimensions were doubled , what would be t

he area of the new rectangle in terms of x ?
Mathematics
1 answer:
iren [92.7K]4 years ago
6 0
Original length: x
original width; x-3
original area: x(x-3)
when the dimensions doubles, that is, increase by a factor of 2, the area increase by 2²
4[x(x-3)]
4x(x-3)=4x²-12x

you can also do it this way:
original length: x        doubled: 2x
original width; x-3      doubled: 2(x-3)
new area: 2x[2(x-3)]= 4x²-12x
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PLS ANSWER
djyliett [7]

Answer: reflection

Step-by-step explanation:

A reflection is like a mirror in the middle you can see they are the same in the line down the middle so <em>reflection </em>

8 0
3 years ago
One factor of One factor of f(x)=5x^3+5x^2-170x + 280 is (x +
SpyIntel [72]

Answer:

x = –7, x = 2, or x = 4 are factors of f(x).

Step-by-step explanation:

Given : f(x)  = 5x³ +5x²-170x +280 and x + 7 is one factor .

To find  : What are all the roots of the function.

Solution :  f(x)  = 5x³ +5x²-170x +280 .

We have given that x + 7 is factor that mean x = -7 is factor of f(x )

When we divide f(x) by x +7 we get

5x² -30x +40 =0

Taking common 5 from equation

5( x² -6x +8) =0

On dividing by 5 both sides

x² -6x +8 = 0

On factoring

x² -2x -4x +8 = 0.

Taking common x from first two terms and -4 from last two terms

x ( x -2) -4 (x -2) = 0

On grouping

(x-2) (x-4) = 0

x -2 =0

x =2

x-4 =0

x = 4

Therefore, x = –7, x = 2, or x = 4 are factors of f(x).

4 0
4 years ago
Read 2 more answers
Which if the filleing equations correctly represents solving q=60-4p for p.
marusya05 [52]

Since no equations were provided, the solution of the equation will depend on the values of p.

<h3>What is the solution of an equation?</h3>

The solution of an equation is the value that makes that equation true.

Given the equation q = 60 - 4p

The solution of the equation will depend on the value of p

For example; if p = 1

q = 60 - 4(1)

q = 56

Therefore, the solution of the equation will depend on the values of p.

learn more about equations at: brainly.com/question/22688504

3 0
3 years ago
AT&amp;T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $
denis-greek [22]

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let x be the number of additional line.

Cost of one additional line = $15

Cost of x additional line = \$15x

Total cost = Fixed cost + Addition cost

                = 125+15x

It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

125+15x\leq 200

Therefore, the correct option is C.

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3 years ago
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