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GenaCL600 [577]
3 years ago
9

Pleasee help with these questions

Mathematics
1 answer:
maw [93]3 years ago
6 0

Answer:

6. 3.14 7. 172.03 8. 78.54 9. 380.13 10. 19.63 11.28.27

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What is the solution of the equation 14^x=5?<br> Round your answer to the nearest ten-thousandth.
deff fn [24]
Take ln to both sides
ln 14^x = ln 5
then you'll get
x ln 14 = ln 5
divide both sides by ln 14
x = 0.6098533345
after rounding
x = 0.6099
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What is the highest common factor of 72 and 90
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Answer:

18

Step-by-step explanation:

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A scale factor that is less than 1, but greater than 0 is​
swat32

Since the scale factor is smaller than one (the original), the resulting image is smaller than the original.

Hope this helped, and feel free to ask more questions if needed(:

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2 years ago
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If g(x) = 2x + 1 and fog (x)=6x-2, find f(x).​
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6 0
1 year ago
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A rectangular enclosure is to be created using 82m rope.
atroni [7]
Let
x-----> the length of rectangle
y-----> the width of rectangle

we know that 
perimeter of rectangle=2*[x+y]
perimeter of rectangle=82 m
82=2*[x+y]---> divide by 2 both sides---> 41=x+y--> y=41-x---> equation 1

Area of rectangle=x*y
substitute equation 1 in the area formula
Area=x*[41-x]----> 41x-x²

using a graph tool
see the attached figure

the vertex is the point (20.5,420.25)
that means
 for x=20.5 m ( length of rectangle)
the area is 420.25 m²

y=420.25/20.5----> 20.5 m

the dimensions are
20.5 m x 20.5 m------> is a square

the answer part 1) 
<span>the dimensions of the rectangular with Maximum area is a square with length side 20.5 meters
</span>
Part 2)<span>b) Suppose 41 barriers each 2m long, are used instead. Can the same area be enclosed?
</span>divide the length side of the square by 2
so
20.5/2=10.25--------> 10 barriers
the dimensions are 10 barriers x 10 barriers
10 barriers=10*2---> 20 m

the area enclosed with barriers is =20*20----> 400 m²

400 m² < 420.25 m²
so

the answer Part 2) is 
<span>the area enclosed by the barriers is less than the area enclosed by the rope
</span>
Part 3)<span>How much more area can be enclosed if the rope is used instead of the barriers
</span>
area using the rope=420.25 m²
area using the barriers=400 m²

420.25-400=20.25 m²

the answer part 3) is
20.25 m²

6 0
3 years ago
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