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Vsevolod [243]
2 years ago
8

Solve the quadratic equation numerically (using tables of x- and y- values). x(x + 6) = 0 a. x = -1 or x = 3 c. x = 0 or x = -3

b. x = 0 or x = 6 d. x =0 or x = -6
Mathematics
1 answer:
Musya8 [376]2 years ago
4 0

Answer:

d. x =0 or x = -6

Step-by-step explanation:

x(x + 6) = 0

This is telling us that either x is 0 or x is -6, because:

1) when x = 0, 0*(0+6)=0, and

2) when x = -6, -6*(-6+6) = 0;  -6(0) = 0

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You have a stack of bills with $1 bills and $5 bills in it. you have 43 total bills equaling $99 how many of each type of Bill d
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Answer:

<u>29</u> $1 bills and <u>14</u> $5 bills.

Step-by-step explanation:

Let x be the number of $1 bills and y be the number of $5 bills. With the information given, we can set up two equations:

1) x+y=43

2) 1x+5y=99

There are two ways to solve it; with elimination or substitution. In this explanation, I will solve it with elimination.

To solve it with elimination, multiply the first equation by 5 to get:

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Then, you can subtract the equation we just got by the second equation to get:

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Thus, x=29. To find y, just substitute x for 29 in the first equation to get:

29+y=43. Therefore, y=14. That means that there are 29 $1 bills and 14 $5 bills. You can check by substituting those values for x and y in either of the first two equations.

Hope this helps :)

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