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Mars2501 [29]
2 years ago
9

Mary got a piggy bank as a gift with X cents in it. If she saves Y cents each month for a year, how much money will she have in

a year?
Mathematics
1 answer:
-BARSIC- [3]2 years ago
3 0

Answer:

The total money she saved in a year = X + 12Y.

Step-by-step explanation:

Mary got a piggy bank as a gift.

Sum of money in the piggy bank while she got it as a gift = X cents

Sum of money she saved = Y cents per month

1 year = 12 months

So, sum of money she saved in 1 year = Y × 12

= 12Y

Hence, the total money she saved in a year = X + 12Y.

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6 0
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Simplify.<br><br> 1/4 (1 - 2/3)² + 1/3.<br><br> The answer must be a simplified fraction.
loris [4]

Answer:

\large\boxed{\dfrac{13}{36}}

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

---------------------------------------------------------------------------

\dfrac{1}{4}\left(1-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3}{3}-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3-2}{3}\right)^2+\dfrac{1}{3}\\\\=\dfrac{1}{4}\left(\dfrac{1}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1^2}{3^2}+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1}{9}+\dfrac{1}{3}=\dfrac{1}{36}+\dfrac{1}{3}\qquad(*)\\\\\text{the common denominator is}\ 36.\\\\36=3\cdot12\to\dfrac{1}{3}=\dfrac{1\cdot12}{3\cdot12}=\dfrac{12}{36}\\\\(*)\qquad=\dfrac{1}{36}+\dfrac{12}{36}=\dfrac{1+12}{36}=\dfrac{13}{36}

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