Answer:
#1: Josue's dogs
#2: see images
#3: Am group median: 25.5 Pm group median: 19
#4: Am group first Quartile = 16 Pm group first Quartile = 10
#5: Am group third Quartile = 30 Pm group third Quartile = 37
#6: see images
#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27
#8: Am group because its Interquartile gruop is smaller than the Pm group
Step-by-step explanation:
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Answer:
1.9 is greater than 1.39 if that's what your asking?
The net change between the given values of the variable is 6a - 6
<h3>How to determine the net change between the given values of the variable?</h3>
The given parameters are
g(x) = 6x
Where
x = 1 and x =a
Calculate g(1) and g(a)
So, we have
g(1) = 6 * 1
g(1) = 6
g(a) = 6 * a
g(a) = 6a
The net change between the given values of the variable is
Change = g(a) - g(1)
So, we have
Change = 6a - 6
Hence, the net change between the given values of the variable is 6a - 6
Read more about functions at:
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Answer:
what are we supposed to answer? im confused.. i can help i just dont know what to answer
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