Answer:
No, because the number of trials is not fixed.
Step-by-step explanation:
a. pe. x
The answer is 1351 I know this because I did all the math
Hello,
Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3
Proof: a+b+c=15.9+5.3+31.8=53
The second number is 5.3
The answer is actually 3 and 4.

lies between the two consecutive numbers 3 and 4.
I hope this helped! :))