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Ronch [10]
3 years ago
14

Do the three lengths form a right triangle? Explain your answer. 10 inches, 24, inches and 26 inches​

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
Yes!
10 x 10 = 100
24 x 24 = 575
100 + 576 = 676
Square root of 676 is 26.
IrinaVladis [17]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

adding this answer so you can mark first guy as beanliest

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What is the measure of &lt;C?<br>​
zlopas [31]

Answer:

m∠C = 38°

Step-by-step explanation:

By the inscribed angle theorem,

"Intercepted arc measures the double of the measure of the inscribed angle"

m(arc AB) = 2[m(∠ACB)]

76° = 2[m(∠ACB)]

m(∠ACB) = 38°

Therefore, measure of angle ACB = 38°.

4 0
3 years ago
The statement “three non-collider points determine a plane” is an example of a
denis-greek [22]
Postulate is the answer
8 0
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Instructure.com
malfutka [58]

Answer:

40%

Step-by-step explanation:

Count the total numbers of tallies. How many tallies you got put over the total number of A&B

Example: A- III B- IIII Total number of the whole chart- IIIII IIIII IIIII

7/15 and then %/100 which would be a number equal to 7/15.

I'm guessing you got the same question as me and my answer was 40%

4 0
3 years ago
Which model represents a fraction less than 3/5?
ycow [4]

3 < 5 if that is what you are contemplating

5 0
3 years ago
Read 2 more answers
A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum heigh
aleksklad [387]

The spider's movement is an illustration of a parabola.

  • The equation of a parabola is: \mathbf{y = -\frac{1}{160}(x - 40) + 10}
  • The focus of a parabola is: (40,-30)
  • The axis of symmetry is: \mathbf{x = 40}
  • The directrix is:\mathbf{y = 50}

<u>(a) The equation</u>

The spider passes through the origin.

So, we have:

\mathbf{(x,y) = (0,0)}

The spider jumps to a maximum height of 10mm, midway 80mm.

So, the vertex is:

\mathbf{(h,k) =  (40,10)}

The equation of a parabola is:

\mathbf{y = a(x - h)^2 + k}

So, we have:

\mathbf{0 = a(0 - 40)^2 + 10}

Subtract 10 from both sides

\mathbf{a(0 - 40)^2 =- 10}

\mathbf{1600a =- 10}

Solve for a

\mathbf{a =- \frac{1}{160}}

Substitute \mathbf{a =- \frac{1}{160}} and \mathbf{(h,k) =  (40,10)} in \mathbf{(h,k) =  (40,10)}

\mathbf{y = -\frac{1}{160}(x - 40) + 10}

<u>(b) The focus, directrix and the axis of symmetry</u>

The focus of a parabola is:

\mathbf{Focus= (h, k + p)}

Where:

\mathbf{p = \frac{1}{4a}}

So, we have:

\mathbf{p = \frac{1}{4 \times -1/160}}

\mathbf{p = -\frac{160}{4}}

\mathbf{p = -40}

So, we have:

\mathbf{Focus = (40,10-40)}

\mathbf{Focus = (40,-30)}

The axis of symmetry is:

\mathbf{x = h}

So, we have:

\mathbf{x = 40}

The directrix is:

\mathbf{y = k - p}

\mathbf{y = 10 + 40}

\mathbf{y = 50}

Read more about parabolas at:

brainly.com/question/25237745

4 0
3 years ago
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