Question

A single die is rolled twice. Find the probability of rolling a 6 the first time and a 3 the second time.

Answer 1

Sounds like a joint event:  First toss produces a 6  AND THEN  second toss prOduces a 3.  These two events are completely independent.

P(6) = 1/6, and P(3) = 1/6

Thus, the probability of rolling a 6 the first time and a 3 the second time is
(1/6)(1/6) = 1/36.

Answer 2

$|\Omega|=6^2=36\\ |A|=1\\\\ P(A)=\dfrac{1}{36}$