The best way to compare fractions is to find the LCM (The Lowest Common Denominator) of each of the fractions. This can be done simply by listing the multiples of the denominators.
Suppose in 1992 Chris was x years old, his brother was then 2x years old. 6 years later in 1998, Chris is (x+6) years old, his brother is (2x+6), (x+6)=(2/3)(2x+6) x+6=(4/3)x+4 (4/3)x-x=6-4 (1/3)x=3 x=6 in 1992, Chris was 6, so in 2018 he will be 6+(2018-1992)=32 years old.
The type of model that best fits the given situation is; A linear equation Model
<h3>What is the model of the equation?</h3>
Right inside the local reservoir we will have an initial amount of water A.
Now, for every hour that passes by, the amount of water in the reservoir decreases by 500 gals.
Thus, after t hours, the amount of water in the reservoir is expressed as:
W = A - 500gal * t
This is clearly a linear equation model and so we can conclude that the model that fits best in the given situation is a linear model.
The domain of this model is restricted because we can't have a negative amount of water in the reservoir, and as such the maximum value of t accepted is: W = 0 = A - 500gal*t
t = A/500 hours
Therefore, the domain of this linear relation is: t ∈ {0h, A/500 }
