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2 years ago

Find the selling price of a suit if a store

Mathematics

2 answers:

Ilia_Sergeevich [38]2 years ago

5 0

I think you multiply 140 and 80% and then add thst to the 140

xz_007 [3.2K]2 years ago

4 0

Answer:

$252

Step-by-step explanation:

The store paid $140 for the suit. Let's first find the 80% of $140.

$140 x 80% = $112

So now we just need to add $112 to $140.

$140 + $112 = $252

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Make y the subject: 5x + 2y = 11

Anton [14]

Does that mean solve for y? If so, here it is:
5x + 2y = 11.

Move the x term by subtracting.
2y = -5x + 11

Divide by 2.
y = -5/2x + 11/2

7 0

2 years ago

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2x2 +5x+8 Given x 3-2, the expression x+2. is equivalent to

Masteriza [31]

Answer:

x=-1

Step-by-step explanation:

so 3-2 is 1 right so what humber + 2 is 1 well -1 becasue -1 + 1 is 0 and plus 2 would be 1 so its -1 (or x= -1). Hope this helped!

6 0

2 years ago

(these are the rest) May i get more help please :( thank you :)

joja [24]

Answer:

7. a = 1,075 sq ft

8. 128 sq ft

9. a = 80 in

10. $28

3 0

2 years ago

Does any one know how to do this. It would be such a life saver if you could help me out. Thx

Aneli [31]

Answer:

1: (3 ,- 4)

2:up (a > o)

3: -4

4: 2 units to the right

5: 4 units down

6: y = (x-2)^2-4

9: (5,9)

10: x=5

11: (4,7) and (6,7)

12:

Step-by-step explanation:

I'm not sure if you wanted it explained or answered , so i just answered most of them. Sorry if you wanted it explained.

3 0

2 years ago

A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil

erma4kov [3.2K]

Answer:

$\frac{n_p}{n_s}=\frac{1}{1000}$

Step-by-step explanation:

Given voltage of primary coil is $V_p=12V$

And voltage of secondary coil is $V_s=12,000V$

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil $(n_p)$ and secondary coil $(n_s)$ .

Following equation represents the relation between them.

$\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}$

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

$\frac{n_p}{n_s}=\frac{1}{1000}$

5 0

3 years ago