Answer:
Step-by-step explanation:
hmmmmm
Remember to include the positive and negative roots
(7x-2)^2=256
sqrt both sides
7x-2=+/-16
add 2 to both sides
7x=2+/-16
divdide both sides by 7
x=(2+/-16)/7)
x=(2+16)/7=18/7=2 and 4/7
x=(2-16)/7=-14/7=-2
x=2 and 4/7 or -2
<h2>
Hello!</h2>
The answer is:
Center: (1,-2)
Radius: 4 units.
<h2>
Why?</h2>
To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

Where,
"h" and "k"are the coordinates of the center of the circle and "r" is its radius.
So, we need to complete the square for both variable "x" and "y".
The given equation is:

So, solving we have:



Now, we have that:

So,
Center: (1,-2)
Radius: 4 units.
Have a nice day!
Note: I have attached a picture for better understanding.
Answer:
Step-by-step explanation:
a. when t=0,h=3ft

c.t=47/32 sec
d.
time taken to fall 2301/64 ft=0*t+\frac{1}{2}*32*t^2
t^2=\frac{2301}{64*16}
t=\frac{\sqrt{2301}}{8*4}=\frac {47.97}{32}
total ~time=\frac{47+47.97}{32}=\frac{94.97}{32} sec
Answer:
x/8 -1
Step-by-step explanation: