Answer:
763/100 is the answer to this
Answer:
i hope it helps you my friend
a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
62
Step-by-step explanation:
62+7000000= 7000062 however when you divide that by its constant of the root of the sqared denominator, you get 4. THENNNN you add 3 to planks constand to get 62.
12, 20, 16, 10, 17, 9, 23, 13
1. add them all up
=120
divide by the number of numbers
120/8
=15
15 is the MAD
