Answer:
c
Step-by-step explanation:
Answer:
4.
°
Step-by-step explanation:
Given:
The tangent of the angle is given as:

Since the angle is negative, it means that it is measured in the clockwise direction as angles measured in clockwise direction are negative and that measured in counter clockwise directions are positive.
-212° when measured from counter clockwise direction will be equal to:

Therefore,
= 
Now, we have the identity for tan as:

Here, 
Therefore,

Hence,
=
=
°
The relation of t as in to what?
N=d-2
q=n+d =>q=(d-2)=q=2d-2
25q+5n+10d=525
replace q and n with d
25(2d-2) +5(d-2)+10d=525
50d-50+5d-10+10d=525
65d=585
d=9
n=7
q=16
Answer:
I'm pretty sure it's (0,1)