So the teacher bought 1/4 of the brownie pan. And it came out to $4.
I hope this helps! :)
Answer:
The subscription began about 10 days before the 15th of the month.
Step-by-step explanation:
The correct option is:
The subscription began about 10 days before the 15th of the month.
The reason for being charged $60 instead of $45 which is the monthly rate is that they started the subscription prior the the cycle date of the bill period. Due to the change in the cycle date, the customer is getting a prorated charge for the days that had service prior to the date of the bill and current cycle starting
Remark
Good thing to know. This is a rounding question.
A
Answer A is a bit nasty. I round 5 to the next highest number on the left. That may not be what you have been told to do. Let us round A to 5.7 and see if anything else does this.
B
Answer B rounds to 5.6
C
Answer C rounds to 5.6 as well. 3 is less than 5 so you round down.
D
Answer D rounds to 5.6(.) The zero has no effect on the 6.
Answer
Since there is nothing special about A and nothing else rounds to 5.7, the answer is A. So your rule is when the last number is 5, you round the second last number to one more than it was, regardless of the properties of the second last number.
The answer is 23.2 I just entered the data into an online standard deviation calculator.
Answer:
<em>The probability of obtaining the letter p twice is 1/121</em>
Step-by-step explanation:
<u>Probability of Recurring Events</u>
There are 11 letters in the word 'independent', one of which is the letter 'p'.
When those letters are written on individual cards and they are put into a box, there are 11 different choices to pick at random.
This means the individual probability of getting a 'p' is:

The card is reinserted into the box, leaving the sample space unaltered, thus the second card has the same probability:

We'll use the multiplication rule. Just multiply the probability of the first event by the second.


The probability of obtaining the letter p twice is 1/121