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Allisa [31]
3 years ago
5

Please help me i have the pic below: find the 27th term given the function an=-10+(n-1)(-2)

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

-62

Step-by-step explanation:

Plug 27 into the equation

a27=-10+(27-1)(-2)

27-1=26

26 times -2 = -52

-52-10=-62

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Jeremy will roll a number cube, numbered 1−6
Marina CMI [18]

Answer:

Step-by-step explanation:

p(even) = 3/6

p  number 3 = 1/6

p (even then number 3) = 3/6 * 1/6 = 3/36

7 0
3 years ago
Write the number in two other forms 6.7
kotegsom [21]
Word form - six.seven Expand form - 6 + 0.7
3 0
3 years ago
If g(x) = 2x2 + 6x + 5, use synthetic division to find g(-5).
diamong [38]
<h3>Answer:  25</h3>

=================================================

Explanation:

Check out the image below. I've posted the synthetic division table. The value at the very end of the bottom row is the remainder. By the remainder theorem, this is exactly the value of g(-5).

Recall the remainder theorem says: If you divide p(x) by (x-k), then the remainder is p(k). In this case, k = -5 is our test root which is the value placed in the box on the left.

As a way to check the answer, we can say

g(x) = 2x^2 + 6x + 5

g(-5) = 2(-5)^2 + 6(-5) + 5

g(-5) = 25

So the answer is confirmed.

6 0
3 years ago
Find the mean, median, and mode for 0, 4, 6, 11, 9, 8, 9, 1, 5, 9, 7. Round to the nearest tenth if needed.
snow_lady [41]

Answer:

6

Step-by-step explanation:

you add them all up and divide it by how many numbers there are

6 0
3 years ago
What is the square root of 95.54
vladimir2022 [97]
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...

They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..

A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:

x-(f(x)/(df/dx))

In a square root problem you wish to know:

x=√n  where x is the root and n is the number

x^2=n

x^2-n=0

So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:

x-((x^2-n)/(2x)) which simplifies further to:

(2x^2-x^2+n)/(2x)

(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)

In this case the number, n=95.54, so a decent starting value for x would be 10.

Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.

10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397

The calculator result for my calc is: 9.7744565066299210578124802523381

So you see how accurate the newton method is in just a few iterations. :P


5 0
3 years ago
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