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Vedmedyk [2.9K]
2 years ago
5

Identify a pair of parallel segments.

Mathematics
1 answer:
AURORKA [14]2 years ago
4 0

say ice wallow come out loud its really funny lol

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Four cards are shuffled and placed face down in front of you. Their faces (hidden) display the four elements: water, earth, wind
Licemer1 [7]

Answer:

probability of winning is\frac{2}{3}

Step-by-step explanation:

As it is given , 4 cards are available,  there are 4!  mean total possible way of ordering is 24  

following are the cases of loosing

1) first card is fire.

Thus there are 3! = mean 6 possible ways for particular ordering  to occur.

2) If wind is first card and Fire is second. Then, There are 2! = 2 ways to occur.

Hence, the probabiIity of losing is given as  = \frac{6+2}{24}=\frac{1}{3}

therefore probality of winning is 1 -\frac{1}{3}

probality of winning is\frac{2}{3}

5 0
3 years ago
The number of kids in a robotics club grew from 23 to 31. What was the percent increase in the number of kids in the club? Round
konstantin123 [22]

Answer: 35\%

Step-by-step explanation:

For this exercise you need to use the following formula:

\%increase=\frac{New\ value-Old\ value}{Old\ value}*100

According to the exercise, the number of kids in a robotics club grew from 23 to 31; then you can identify that:

New\ value=31\\\\Old\ value=23

Knowing these values, you can substitute them into the equation and then evaluate, in order to find the percent increase in the number of kids in the club. Then:

\%increase=\frac{31-23}{23}*100\\\\\%increase=34.78\%

Rounding it to the nearest whole percent:

\%increase=35\%

8 0
3 years ago
A car agency shows a new car with a price of AED 45,000. The company predicted that the cost of the
AleksandrR [38]

Answer:

$8640

Step-by-step explanation:

<u>Step 1</u>:

The total amount of the car currently is $45,000. The car depreciates by 10% for the next 3 years. Then multiply 3 to 45,000.

3 × 45,000 = 135,000

The price then decreases by 10%. So, find 10% of 135,000

10\% = \frac{10}{100}

135000=\frac{135000}{1}

\frac{10}{100}\times \frac{135000}{1}

Cross cancel the zeros

\frac{10}{1}\times \frac{1350}{1}

Multiply across

10\times1350 = 13500

Therefore, for the three years, the cars price is now $13,500.

<u>Step 2</u>:

The next step is the same as the first one. But now the car currently is $13,500. And The car depreciates by 8% for the next years. We have to find the value in 8 years. Then multiply 8 to 13,500.

8 × 13,500 = 108,000

Now, find 8% of 108,000

8\% = \frac{8}{100}

108000=\frac{108000}{1}

\frac{8}{100}\times \frac{108000}{1}

Cross cancel the zeros

\frac{8}{1}\times \frac{1080}{1}

Multiply across

8\times1080 = 8640

Therefore, the value of the vehicle in 8 years is $8640.

7 0
2 years ago
What is the simplified form of (-9m^1/2n^4/5)(2m^1/3n^2/5)
ira [324]
It is -3m2n6
_______
25

7 0
3 years ago
Read 2 more answers
Can you help thank you &lt;3
Andrews [41]

Answer:

g=2.5 yes its corrects

Step-by-step explanation:

11.8-9.3=2.5

5 0
2 years ago
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