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AfilCa [17]
4 years ago
9

Helpieeeeeeeeeeeeeeeee plzzzzzzzzzzzz owo Will make brainlist

Mathematics
1 answer:
maria [59]4 years ago
7 0

<em>Answer:</em>

<em>9x^2-3x - 12</em>

<em>Step-by-step explanation:</em>

<em>(9x^2 + 6x - 7) + (-9x -5)</em>

<em>Simplify the expression:</em>

<em>9x^2 - 3x - 12</em>

<em>Factor:</em>

<em>Add and subtract the second term to the expression and factor by grouping.</em>

<em>3( x + 1 ) ( 3x - 4 )</em>

<em>Standard form:</em>

<em>9x^2 - 3x - 12</em>

<em>I hope this helps :) </em>

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<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

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<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

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( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

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Perimeter\ of\ R=2(5x)

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We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

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\text{Area\ of\ Rectangle}=6x^2

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=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

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