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3 years ago

Help, if you don't know. Pls don't answer!! I need help quick!!!

Mathematics

1 answer:

fredd [130]3 years ago

7 0

(y1 - y2) / (x1 - x2) = slope

(-1 - 3) / (4 - 2)

-4 / 2

<em>-2</em>

Hope this helps! :)

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Please help me ASAP!!!<br> Solve for y.<br> −4.2y+2.1>−2.52

Maru [420]

Answer:

hope it helps you

Step-by-step explanation:

https://mathsolver.microsoft.com/en/solve-problem/-4.2y%2B2.1%20%3E%20%20-2.52

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3 years ago

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A student uses a solution that contains 16 grams of water to conduct an evaporation experiment. At the end of one hour, the am

yanalaym [24]

Answer:

3.5% decrease means 96.5% remaining

0.965(16)

4.25% decrease means 95.75% remaining

0.9575(0.965(16))

= 14.7838 grams

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3 years ago

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How do you solve? Help?

Vinvika [58]

Plug in a -20 wherever you see a b
(-20)^2 +4*-20-89/13
400 + -80-89/13
400 - 169/13
400-13
=387

Hope this helps

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3 years ago

The temperature in Minnesota was -8°F one day. On the same day, the temperature was 12° higher in Indiana. What was the temperat

ahrayia [7]

Answer:

Step-by-step explanation:

-8 +12=4

there has to be 20 characters so thi is what I'm putting.

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3 years ago

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Solve x'=5t(sqrt(x)) x(0)=1

LekaFEV [45]

Answer:

$2\sqrt{x}=\frac{5t^2}{2}+2$

Step-by-step explanation:

Given: $\frac{\mathrm{d} x}{\mathrm{d} t}=5t\sqrt{x}\,,\, x(0)=1$

Solution:

A differential equation is said to be separable if it can be written separately as functions of two variables.

Given equation is separable.

We can write this equation as follows:

$\frac{dx}{\sqrt{x}}=5t\,dt$

On integrating both sides, we get

$\int \frac{dx}{\sqrt{x}}=\int 5t\,dt$

Formulae Used:

$\int \frac{1}{\sqrt{x}}=2\sqrt{x}\,\,,\,\,\int t\,dt=\frac{t^2}{2}$

So, we get solution as $2\sqrt{x}=\frac{5t^2}{2}+C$

Applying condition: x(0) = 1, we get $C=2$

Therefore, $2\sqrt{x}=\frac{5t^2}{2}+2$

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3 years ago