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3 years ago

Can someone please help me!

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

Standered Notation

1. 2.5 x 10 x 10 x 10

2. 3.442 x 10 x 10 x 10 x 10

Scientific notation

1. 4.59 × 10^9

2. 3.442 × 10^4

Step-by-step explanation:

Brainiest please.

maks197457 [2]3 years ago

6 0

2500
34420
4.59*10^9
3.442*10^4

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Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both, in case

lozanna [386]

Answer:

0.3339 = 33.39% probability that both Dave and Mike will show up

Step-by-step explanation:

Probability of independent events:

If A and B are independent events, the probability of both happening at the same time is given by:

$P(A \cap B) = P(A)P(B)$

In this question:

Event A: Dave shows up.

Event B: Mike shows up.

Christine knows that there is a 47% chance that Dave will not show up and a 37% chance that Mike will not show up.

This means that $P(A) = 1 - 0.47 = 0.53, P(B) = 1 - 0.37 = 0.63$ .

a. What is the probability that both Dave and Mike will show up

$P(A \cap B) = P(A)P(B) = 0.53*0.63 = 0.3339$

0.3339 = 33.39% probability that both Dave and Mike will show up

8 0

2 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

monitta

Answer:

a) n =1623

b) $ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208$

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken

$\hat p=0.19$ estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by $\alpha=1-0.96=0.04$ and $\alpha/2 =0.02$ . And the critical value would be given by: