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blsea [12.9K]
3 years ago
12

Solve for x ................

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Step-by-step explanation:

complementary angles are 90°,supplementary are 180°

(3x+25)+2x=180(supplementary angles)

2x +3x is 5x

5x=180-25=155

5x=155÷5=31

x=31

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Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x
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Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

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Answer:

The roots of a quadratic equation simply tell what values of x will make the equation true. A quadratic function is a function where the largest power for the variable is 2. ... A quadratic equation is given to you so that you can solve it for the variable. A quadratic function is given to you so that you can graph it.

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3 years ago
A rhombus has a side length equal to one of the diagonals. The other diagonal is 4cm longer. Find the area of the rhombus.
klasskru [66]

Answer:

The area of the rhombus is 25.83 cm².

Step-by-step explanation:

The area of a rhombus is given by:

A = \frac{d_{1} \times d_{2}}{2}

Where:      

d₁: is one diagonal      

d₂: is the other diagonal = d₁ + 4 cm

We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:

h: hypotenuse of the right triangle  

a: one side of the right triangle

b: is the other side of the right triangle  

From the above we know that:

h = d₁                                

a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2}

b = \frac{d_{1}}{2}            

We can find d₁ with Pitagoras:

h^{2} = a^{2} + b^{2}  

d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2}

d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2})

By solving the above quadratic equation for d₁ and taking the positive solution we have:

d_{1} = 5.46 cm    

So, d₂ is:

d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm

Now, we can find the area:

A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2}

Therefore, the area of the rhombus is 25.83 cm².

I hope it helps you!  

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Answer:

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Step-by-step explanation:

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