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Ipatiy [6.2K]
2 years ago
9

The vertices of triangle are A(-2 , 1 ) , B ( 2 , 2 ) and C ( 6 , -2 ) . Find the equation of the altitude of AD drawn from A to

BC.
Please help!!:)​
Mathematics
1 answer:
krok68 [10]2 years ago
7 0

Answer:

Given,

ABC is triangle with vertices A(-2,1), B(2,2) and C(6, -2)

Slope of BC(m_1) =\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{-2-2}

=\frac{4}{-4}=-1

Since AD is perpendicular to BC

let slope of BC be (m_2).

We have for perpendicular

m_1*m_2=-1

-1*m_2=-1

m_2=1

Now equation of line passing through point A(-2,1) is

y-y_1=m_2(x-x_1)

y-1=1(x-(-2))

y-1=x+2

y=x+2+1

y=x+3 which is a required equation of the altitude of AD drawn from A to BC.

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