All categories

2 years ago

Which is better buy? 5 lb of flour for $0.90 or 8 lb for $1.25

Mathematics

2 answers:

lutik1710 [3]2 years ago

7 0

Answer:

The answer is 1.25

So if you have 5lbs for $0.90 you want to find the price of one, which would be 0.18 cents because 0.90 divided by 5 is 0.18. 8lbs for $1.25 you need to divide by 8 and you get 0.15625, but just simply to 0.15 or 5/32. So the second one is the better buy.

Ludmilka [50]2 years ago

4 0

Well let’s see if there’s a least common multiple of 5 and 8. Since 40 is the least common mult. We will multiply 40 x .90 and 40 x 1.25 . 40x.90 is 36 while 40x1.25 is 50. It’s better to buy eight pounds for 1.25!

You might be interested in

Multiply and simplify. (x + 3)(x - 8)

Kazeer [188]

Answer:

$x^{2} - 5x - 24$

Step-by-step explanation:

( x + 3 )( x - 8 ) =

$x^{2}$ - 8x + 3x - 24 = $x^{2}$ - 5x -24

4 0

3 years ago

This is the graph of y = sin(x). Does anyone know the second part?

Alborosie

Answer:

The resulting graph is $y = 5\cdot \sin x$ .

Step-by-step explanation:

The resulting function is of the form:

$y = A\cdot \sin x + k$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$A$ - Amplitude, dimensionless.

$k$ - Midpoint value, dimensionless.

The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: $A > 0$ . According to the graph, the function is bounded between 5 ( $y_{max}$ ) and -5 ( $y_{min}$ ), and the midpoint value ( $k$ ) is 0. The amplitude is determined by the following calculation:

$A = \frac{y_{max}-y_{min}}{2}$

If $y_{min} = -5$ and $y_{max} = 5$ , then:

$A = 5$

The resulting graph is $y = 5\cdot \sin x$ .

6 0

2 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

3 years ago

Choose the correct formula for the function g.

sleet_krkn [62]

Answer:

Step-by-step explanation:

I typed it into a graphing calculator. You could also choose a point (I choose (4,0) ) then plug it into each equation In the answers until you get back the numbers of the point you choose to represent x and y. For example

5 0

3 years ago

6 and 1/4 - 2 and 3/4 what is the answer please

Yuki888 [10]

Answer:

The answer to the problem is 3 1/2

8 0

3 years ago

Read 2 more answers