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ratelena [41]
3 years ago
14

What is the slope of a line that is perpendicular to a line whose equation is 5y=10+2x ?

Mathematics
2 answers:
Andru [333]3 years ago
6 0

Answer:

The answer is -\frac{5}{2}


Jet001 [13]3 years ago
4 0
The slope is 2 because the slope is always next to the x
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Which value is equivalent to x+4/4+x?<br><br> A. -4<br> B. -1<br> C. 1<br> D. 4
MaRussiya [10]

Answer:

Hello :

(x+4)/(4+x) = (x+4)/(x+4)  = 1   ( answer : C )  but x+4 no : 0



3 0
3 years ago
Read 2 more answers
I need help answer all of them plz
klemol [59]

Answer:

Step-by-step explanation:

1a. 25/50 =x/100                

25*100= 2500/50= 50

A= 50%

1b. 35/40 = x/100

35*100= 3500/40= 87.5

A=87.5%

2a. 15/20= x/100

20*5= 100; 15*5= 75

A=75%

2b. 25/70= x/100

25*100= 2500/70= 35.71

A=35.71

3a. 15/80= x/100

15*100= 1500/80=18.75

A=18.75%

3b. 30/60= x/100

30/60= 1/2;1/2=0.5;0.5= 50%

A=50%

4a. 70/80 =x/100

70*100=7000/80 =87.5

A=87.5

4b.30/60 = 50% ( same as question #3b)

5 0
3 years ago
Solve the proportion. 8/11 = 4/y + 2
Rashid [163]

Answer:

The answer is Y = - (22)/(7 )

Step-by-step explanation:

The parenthesis do not mean anything write 22/7 as a fraction.. why did you report my answer so rude

4 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
Peter buried a treasure chest on a remote island and is.making a map so he can find it later. One of the key landmarks in the ar
PIT_PIT [208]
Where’s the rest of the question?
5 0
2 years ago
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