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tiny-mole [99]
2 years ago
8

{x^{2}-8x+16 }{x^{2}-7x+12 }" alt="\frac{x^{2}-8x+16 }{x^{2}-7x+12 }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
trapecia [35]2 years ago
8 0

Answer:

\frac{x - 4}{x - 3}

Step-by-step explanation:

\frac{ {x}^{2} - 8x + 16 }{ {x}^{2}  - 7x + 12}

Lets split the numerator and denominator.

=  >  \frac{ {x}^{2}  - 4x - 4x + 16}{ {x}^{2}  - 3x - 4x + 12}

Lets factorise the numerator and denominator.

=  >  \frac{x(x - 4) - 4(x - 4)}{x(x - 3) - 4(x - 3)}

=  >  \frac{(x - 4)(x - 4)}{(x - 3)(x - 4)}

Cancelling x - 4 from numerator and denominator ,

=  >  \frac{x - 4}{x - 3}

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