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uranmaximum [27]
3 years ago
7

Please help me I don't know how to do this! Find the measure of the angles.

Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

which angles do you mean its kinda confusing

Step-by-step explanation:

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Write an inequality for the sentence. <br><br> c is not less than zero.
Zepler [3.9K]

c  \leqslant 0
6 0
3 years ago
!*I NEED HELP AND QUICK*!
rewona [7]
1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2

3) (11 1/2)*12 area of the one  type of the wall, there are 2 such walls
 (11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2

Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476

Tamara needs total 476  square feet, which is less than 480 square feet, so she has enough paint.



5 0
4 years ago
(-4,6); slope = -3/4​
yawa3891 [41]

Answer:

y-6=-3/4(x+4)

Step-by-step explanation:

y-y1=m(x-x1)

m=-3/4

y-6=-3/4(x-(-4))

y-6=-3/4(x+4)

6 0
3 years ago
What is the mean median mode range of 3,14,7,12,4,9,16,4,8,20
gogolik [260]

First, order the number set from least to greatest:

3 , 4 , 4 , 7 , 8 , 9 , 12 , 14 , 16 , 20

Mean: You find the mean by combining all the terms, and dividing by the amount of the terms there are in the number set:

(3 + 4 + 4 + 7 + 8 + 9 + 12 + 14 + 16 + 20)/10

(97)/10 = 9.7

Mean: 9.7

Median: You find the median by first ordering the number set from least to greatest, and finding the middle number. Note that if there is a even number of numbers in the set, you find the mean with the two given median digits:

8 & 9 are the median numbers:

(8 + 9)/2 = (17)/2 = 8.5

Median: 8.5

Mode: The mode is the number(s) in the set that shows up the most:

Mode: 4 (shows up one more time than all other numbers)

Range:  The range can be found by subtracting the least number from the greatest number in the number set:

Range: 20 - 3 = 17

Range: 17

~

5 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
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