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stich3 [128]
3 years ago
14

for a March past competition on sports day the house captain of one house cut 25 pieces of ribbon each 1/2 metre in length.what

was the length of ribbon cut altogether​
Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

not lenguague spanish

Step-by-step explanation:

that bad

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Jimmy has a piece of string that is 6 3/4 inches long, and Sam has a piece of string that is 7 1/2 inches long.
mafiozo [28]

Answer:

3/4 inches

Step-by-step explanation:

Subtract Jimmys string length from Sam's string length

7 1/2 - 6 3/4

Get a common denominator of 4

7 1/2*2/2 - 6 3/4

7 2/4 - 6 3/4

Borrow 1 ( or 4/4) from the 7

6 4/4 + 2/4 - 6 3/4

6 6/4 - 6 3/4

3/4

6 0
3 years ago
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John has 2456 pennies in his coin collection he has the same number of pennies in each of the three boxes estimate to the neares
Keith_Richards [23]
If I read correctly, 2456 pennies needs to be divided simply by 3 then rounded to the nearest hundredth. So you would do 2456/3 3 goes into 24 how many times? Then 3 goes into 5 how many times, then continue the pattern. Once you've gotten a decimal to the thousandth, round the number to the hundredth and there you go
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3 years ago
HELPPPPPP PLEASEEEE HELP HELP
Delvig [45]

Answer:

i believe the answer is 3pi/4

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3 years ago
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

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3 years ago
The teachers sold 32 tickets this is 80% of the tickets given to the teachers how many tickets were given to the teachers
UkoKoshka [18]
You would give the teacher 40 tickets
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3 years ago
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