Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
Answer:
Step-by-step explanation:
The largest factor that will divide evenly into both 32 and 48 is 16.
Thus, 32 - 48 = 16(2 - 3), or 16 (-1), or just -16.
Are you sure there wasn't more to this problem?
Part (b)
We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.
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This means,
is the solution with the initial condition y(0) = 0.
Answer:
3
Step-by-step explanation:
15x +8 =40 +13
15x + 8=53
15x=45
3
