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The gear is one of the oldest mechanical devices. It has been used since ancient times for its ability to increase or decrease r

eduard

The large gear attached to the pedals connected to the smaller gear

attached to the wheel allows the bicycle to travel further per rotation.

Correct responses:

Part A: Approximately 10.47 inches

Part B: 300°The d

Part C: Approximately 125.66 inches

Part D: The distance traveled increases by approximately 62.83 inches

<h3 /><h3>Methods used to calculate the above values</h3>

Given:

The radius of the large central gear, <em>r</em> = 4 inches

Radius of the small gear = 2 inches

Part A:

The distance travelled by the larger gear when the angle of rotation is 150° is given as follows;

$\displaystyle Distance \ travelled \ by \ larger \ gear = \mathbf{\frac{150^{\circ}}{360^{\circ}} \times 2 \times \pi \times 4 \, inches} = \frac{10}{3} \cdot \pi \ inches$

$\displaystyle Distance \ traveled \ by \ the \ outer \ edge = \frac{10}{3} \cdot \pi \ inches \approx \underline{ 10.47 \ inches}$

Part B:

When the small gear travels the same linear distance as the large gear in part A, we have;

$\displaystyle Degree \ of \ rotation = \frac{\frac{10}{3} \cdot \pi }{2 \times \pi \times 2 } \times 360^{\circ}= 300^{\circ}$

The degree of rotation of the small gear = <u>300°</u>

Part C:

The distance travelled, <em>C</em>, by a single rotation of the large gear is given as follows;

C = 2 × π × 4 inches = 8·π inches

The degree of rotation of the smaller gear following one rotation of the large gear is therefore;

$Degree \ of \ rotation = \displaystyle \frac{8\cdot \pi \ inches}{4 \cdot \pi \ inches } \times 360^{\circ} = \mathbf{ 720^{\circ}}$

720° = 2 × 360°

1 complete rotation is equivalent to 360°.

Therefore'

720° is equivalent to two complete rotation.

Therefore, the smaller gear and the wheel rotates twice for each rotation of the large gear

The distance the bicycle travels = 2 × The circumference of the wheel

Therefore;

Distance traveled by the bicycle = 2 × 2 × π × 10 inches = 40·π inches

Distance traveled by the bicycle = 40·π inches ≈ <u>125.66 inches</u>

Part D:

If the radius of the small gear is 1.5 inches and the radius of the large gear is 4.5 inches, we have;

Number of rotation of the small gear for each rotation of the large gear = 3 rotations

Therefore, number of rotation of the wheel = 3

Distance the bicycle travels = 3 × 2 × π × 10 inches = 60·π inches

The difference in distance traveled = 60·π inches - 40·π inches = 20·π inches

The distance traveled by the bicycle increases by 20·π inches ≈ <u>62.83 inches</u>

Learn more about gear transmission here:

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8 0

3 years ago

There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

We have given that:

There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp. Each year, 10 new crocodiles join the swamp

Part A:

According to the above mentioned statement the function for representing the number of alligators and crocodiles in the swap throughout the year is:

Alligators = y=20(1.25)^x (x represents years)

crocodiles: y=10x+25

Part B:

Number of alligators after 4 years in the swap = y=20(1.25)^x

Number of alligators after 4 years in the swap = y=20(1.25)^4

Number of alligators after 4 years in the swap=48.82

This shows that about 48 to 49 alligators will be there in the swap after 4 year

Number of crocodiles after 4 years in the swap = y= 10(4)+25 = 65

Part C:

We will use the graph method to solve this part:

After approximately 7 years, the number of animals of each type will be the same, 95.

7 0

3 years ago

A student counted the number of times her teacher said word like during her class over an 11- day period [likes per class period

hichkok12 [17]

Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.

5 0

3 years ago

Read 2 more answers

ABC is reflected across x = 1 and y = -3. What are the coordinates of the reflection image of B after both reflections?A. (-7, -

Dima020 [189]

Answer:

The correct option is C.

Step-by-step explanation:

From the given figure it is noticed that the coordinates of B are (-5,-7).

If ABC is reflected across x = 1, then

$(x,y)\rightarrow(1-(x-1),y)$