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3 years ago

What are the largest numbers for each of the following sums of three consecutive numbers: n Correct answer is brainliest

Mathematics

1 answer:

Andreyy893 years ago

7 0

Answer:

so where are the 3 consecutive numbers?

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QUESTION 20

Elodia [21]

Answer:

B. -55

Step-by-step explanation:

La resta entre ambas funciones consiste en la sustracción de términos semejantes como demostraremos a continuación:

1) $f(x) =-2\cdot x ^{2}-6$ Dado

2) $g(x) = x+4$ Dado

3) $(f-g)(x) = (-2\cdot x^{2}-6)-(x+4)$ Definición de resta de funciones.

4) $(f-g)(x) = (-2\cdot x^{2}-6)+(-1) \cdot (x+4)$ $(-1)\cdot a = -a$

5) $(f-g)(x) = (-2\cdot x^{2}-6) + (-x-4)$ Propiedad distributiva/ $(-1)\cdot a = -a$

6) $(f-g)(x) = -2\cdot x^{2}-x+(-6-4)$ Propiedad conmutativa

7) $(f-g) (x) = -2\cdot x^{2}-x-10$ Sustracción de términos semejantes/Resultados.

A continuación, evaluamos la función resultante en $x = -5$ :

$(f-g)(-5) = -2\cdot (-5)^{2}-(-5)-10$

$(f-g)(-5) =-55$

Por ende, la respuesta correcta es B.

8 0

3 years ago

30% of $40 is blank money

Masja [62]

Answer:

Step-by-step explanation:

30% is 0.3, 40 x 0.3 . is 12 :DD

8 0

3 years ago

1/8 into a decimal work

sergey [27]

Your answer is 0.125

4 0

3 years ago

Find the value of x.<br><br> Can someone help please?

Leya [2.2K]

A. is the correct answer

5 0

2 years ago

Use emilimination to solve 2t 3n=9 and 5t-3n=5

Vladimir [108]

2t+3n=9 2(2)+3n=9
+5t-3n=5 (the 3n cancel out) 4+3n=9
7t=14 3n=5
t=2 n=5/3 or 1.67

3 0

3 years ago