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PilotLPTM [1.2K]
3 years ago
13

The height reached by the rocket depends on the amount of fuel

Mathematics
2 answers:
emmasim [6.3K]3 years ago
4 0
Initial displacement = dboost = v0t + 1/2at^2 
<span>hboost = dboost sin theta </span>
<span>xboost = dboost cos theta </span>
<span>vboost = v0 + at </span>
<span>vxboost = vboost cos theta </span>
<span>vyboost = vboost sin theta </span>

<span>To get the maximum altitude, use conservation of energy </span>
<span>initial PE + vertical KE </span>
<span>= mg (hboost) + 1/2 m vyboost^2 </span>
<span>= final PE = mg (hfinal) </span>

<span>hfinal = hboost + vyboost^2 / 2g </span>
<span>= hboost + ((v0 + at) * sin (theta))^2 / 2g </span>

<span>b) flight time = </span>
<span>boost time + time to rise ballistically from hboost to hfinal </span>
<span>+ time to fall from hfinal </span>

<span>The time to fall a distance h can be gotten by: </span>
<span>h = 1/2 gt^2, so t = sqrt (h/2g) </span>

<span>So flight time = t + sqrt ((hfinal - hboost)/2g)+ sqrt (hfinal/2g) </span>

<span>Horizontal range = xboost + vxboost * time of ballistic flight </span>

<span>= (v0t + 1/2at^2) cos theta </span>
<span>+ (v0 + at) cos theta * (sqrt ((hfinal - hboost)/2g)+ sqrt (hfinal/2g)) </span>

<span>Lots of plugging and chugging to do now. </span>

<span>EDIT--the problem said acceleration was constant, so we don't have to worry about loss of mass during the boost. Realistic? No. But that's what the problem says. Once the thing is ballistic, it's a moot point anyway

</span>
gavmur [86]3 years ago
3 0
True as u cant have a rocket flying at a high height if its low on fuel as if the fuel runs out mid flight they will just crash

brainliest:))))))))


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Sean used 1-3/4 cup of sugar to make a dozen brownies. How many cups of sugare are used for 6 dozen brownies?
alisha [4.7K]

Answer:

10 1/2

Step-by-step explanation:

We need to convert 1 3/4 to an improper fraction

1 3/4 = (4*1+3)/4 = 7/4

Multiply this by the number of batches

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Change this back to a mixed number

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10 1/2

7 0
3 years ago
find the probability if two dice are rolled. (enter the value of probability in decimals. round the answer to three decimal plac
spayn [35]

The probability of getting a total of 8 when two dice are rolled is 0.139.

Probability is a number that expresses the likelihood or chance that a specific event will take place. Probabilities can be represented by proportions on a 0–1 scale.

A single die will have six sides with the numbers: 1, 2, 3, 4, 5, and 6. Each of these events is equally likely to occur if the dice are rolled fairly. So the probability of getting any side of the number is 1/6. Therefore, the probability of getting 1 in dice is 1/6, 2 is 1/6, and so on.

Therefore, the total possible outcomes are the multiplication of the total possible outcomes on dice 1 and dice 2, which is 36.

This possible outcome of rolling two dice is given by,

\left\{\begin{array}{ccccccc}(1, 1)&(1, 2)& (1, 3)&(1, 4)&(1, 5)&(1, 6)\\(2, 1)&(2, 2)&(2, 3)&(2, 4)&(2, 5)&(2, 6)\\(3, 1)&(3, 2)&(3, 3)&(3, 4)&(3, 5)&(3, 6)\\(4, 1)&(4, 2)&(4, 3)&(4, 4)&(4, 5)&(4, 6)\\(5, 1)&(5, 2)&(5, 3)&(5, 4)&(5, 5)&(5, 6)\\(6, 1)&(6, 2)&(6, 3)&(6, 4)&(6, 5)&(6, 6)\end{array}\right\}

The probability of getting a total of 8 from both dice is given by, (2, 6) (3, 5) (4, 4) (5, 3) (6, 2). So the number of favorable outcomes is 5 and the total outcome is 36. The probability is P(getting a total of 8 from both dices)=5/36= 0.139.

The answer is 0.139.

The complete question is -

Consider rolling dice and getting a total of 8. Find the probability of two dice are rolled. (Enter the value of probability in decimals. Round the answer to three decimal places).

To know more about dice probability:

brainly.com/question/17239706

#SPJ4

8 0
1 year ago
In a school with 117 seventh-grade students and about 29 students per class, the number of seventh-grade classes is about
notka56 [123]

Answer - 4 classes

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That is the answer. hope this helps.

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14x^7
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Find the value of y if the value of x is 2 for each equation and match it with the appropriate result.
Xelga [282]

9514 1404 393

Answer:

  3, 0, 2, -2

Step-by-step explanation:

Put x=2 into each equation and solve for y.

<u>2 + y = 5</u>

  y = 5 -2

  y = 3

<u>3x +2y = 6</u>

  3·2 +2y = 6

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  y = 0

<u>2x +y = 6</u>

  2·2 +y = 6

  y = 6 -4

  y = 2

<u>5x +3y = 4</u>

  5·2 +3y = 4

  3y = 4 -10 = -6

  y = -2

4 0
3 years ago
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