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Bas_tet [7]
3 years ago
6

N a northwestern U.S. town, the peak temperature is 96° Fahrenheit in August. After the peak, it drops an average of 4° Fahrenhe

it per week. The graph below models the number of weeks it would take the temperature to drop below freezing, 32° Fahrenheit.
10111213141516171819202122

Which of the following is the correct interpretation of the solution?
A.
It would take less than 16 weeks to drop below freezing.
B.
It would take more than 16 weeks to drop below freezing.
C.
It would take 16 or more weeks to drop below freezing.
D.
It would take 16 or less weeks to drop below freezing.
Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0

Answer:

It would take more than 16 weeks to drop below freezing.

Step-by-step explanation:

The temperature is dropping from 96°F to 32°F at a rate of 4°F per week, where 32°F is the freezing point.

Hence, 32 = 96 - 4w { Where w week is required to reach 32°F }

⇒ 4w = 64  

⇒ w = 16

Therefore, it would take more than 16 weeks to drop below freezing. ( Answer )

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The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Step-by-step explanation:

When a terminal side of an angle intersect the unit circle at

point (x , y), then:

  • The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
  • The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
  • If x and y coordinates are positive, then the angle lies in the 1st quadrant
  • If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
  • If x and y coordinates are negative, then the angle lies in the 3rd quadrant
  • If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant

∵ The terminal ray of angle Ф intersects the unit circle at point (\frac{-\sqrt{2} }{2},\frac{\sqrt{2} }{2})

- According to the 1st and 2nd notes above

∴ cosФ = x-coordinate of the point

∴ sinФ = y-coordinate of the point

∵ The x-coordinate of the point is negative

∵ They-coordinate of the point is positive

- According the the 4th note above

∴ Angle Ф lies in the 2nd quadrant

∵ x-coordinate = \frac{-\sqrt{2} }{2}

∴ cosФ = \frac{-\sqrt{2} }{2}

∵ y-coordinate = \frac{\sqrt{2} }{2}

∴ sinФ = \frac{\sqrt{2} }{2}

- cotФ is the reciprocal of tanФ

∵ tanФ = sinФ ÷ cosФ

∴ cotФ = cosФ ÷ sinФ

∴ cotФ = \frac{-\sqrt{2} }{2} ÷ \frac{\sqrt{2} }{2}

∴ cotФ = -1

The values of cosine Ф and cotangent Ф are \frac{-\sqrt{2} }{2} and -1

Learn more:

You can learn more about the trigonometry function in brainly.com/question/4924817

#LearnwithBrainly

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Answer:

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Given

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a(r) = nr^2

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From the question, we have:

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and

a(r) = nr^2 --> area from radius

The interpretation of the question is to find the composite function: a(t)

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As per the problem

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