Question

Three red,ten white, five blue and two green counters are put into a bag, and one is picked at random. Calculate the probability that it is:
i) a white counter

ii) a red counter

iii) Are the outcomes equally likely?

Answer 1

Answer:

(i) 1/2

(ii) 3/20

Step-by-step explanation:

(i) given total number of white counters = 10

total outcomes = 20 (3+10+5+2)

so it's 10/20

by simplifying it we get 1/2

(ii) given total number of red counters = 3

so it's 3/20