According to these measures, is it possible that the heaviest piece of fruit in the two samples was an orange? Explain why or wh
1 answer:
Answer:
Yes,
Step-by-step explanation:
The measures given which are median and interquartile range have no effect on what the maximum value of a certain distribution will be.
In essence, the information given about the samples of fruits and apples do not point to which fruit sample should possess the sample with maximum weight as the information only gives a general description of each distribution. This means that either samples of orange or apple could have the heaviest piece of fruit.
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m x H =
Step-by-step explanation:
Step 1; Multiply 5 with this matrix and we get a matrix
Multiply the fraction with the matrix
and we get
Step2; Now equate corresponding values of the matrices with each other.
-5 = and so on. By equating we get the value of m as
Step 3; Add the matrices to get the value of matrix m.
Adding the three matrices on the RHS we get .
Step 4; Adding the matrices on the LHS we get the resulting matrix as H +
. Equating the matrices from step 3 and 4 we get the value of H as
Step 5; Now to find the value of m x H we need to multiply the value of with the matrix
Step 6; Multiplying we get the matrix m x H = [ -25
]