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zhannawk [14.2K]
3 years ago
15

Please can someone help me with his i really need it

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

0.34

Step-by-step explanation:

iff we think of them all as a percentage then it looks like

25% + 17% + 21% + 3%

then you add them to get 66%

now you know you are missing 34% to make up the rest of the area.

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The product of 5 and a number less 6 is 4. write the phrase as an algebraic equation.
kvasek [131]
5 + x - 6 = 4
x= 5

5 plus 5 equals 10 and 10 minus 6 is equal to 4.
3 0
3 years ago
Read 2 more answers
How do you get 3630 from 726x5 like can you explain it
Stella [2.4K]

Answer:

3630

Step-by-step explanation:

726*5

= (700+20+6) * 5

= (700*5) + (20*5) + (6*5)

= 3500 + 100 + 30

= 3600 + 30

= 3630

4 0
3 years ago
Answer it and show your work. Which letter choice is it.
ivanzaharov [21]

Answer:

b = 55 degrees

Step-by-step explanation:

The angles 30, a, b and 45 must sum up to 180 degrees

Subtracting (30 + 45) from both sides leaves us with a + b = 105 degrees.

But b = a + 5.  Substituting a + 5 in the equation above yields

a + a + 5 = 105 degrees, so that

2a = 100 degrees, and a = 50 degrees.  Then b = a + 5, or b = 55 degrees.

7 0
3 years ago
Translate this phrase into an algebraic expression.
Roman55 [17]

Answer:

8+2j like you say let j be the variable and more than means+

7 0
3 years ago
Read 2 more answers
Solve the following equations;-<br><br> x - 9 /√x + 3 =1
fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1

Cross multiply ,

\sf\implies x - 9 =\sqrt{ x +3}

Squaring both sides ,

\sf\implies (x - 9)^2 = x + 3

Simplify the whole square ,

\sf\implies x^2+9^2-2.9.x = x +3 \\

\sf\implies x^2+81 - 18x = x -3

Add 3 and subtract x on both sides ,

\sf\implies x^2 -18x-x +81-3=0

Simplify ,

\sf\implies x^2 -19x +78=0

Split the middle term of the quadratic equation,

\sf\implies x^2-13x-6x+78=0

Take out common ,

\sf\implies x( x -13)-6(x-13)=0

Take out ( x -13 ) as common ,

\sf\implies ( x -13)(x-6)=0

Equate both factors to 0 ,

\sf\implies \boxed{\pink{\sf x = 13,6}}

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>x</u><u> is</u><u> </u><u>1</u><u>3</u><u> </u><u>or </u><u>6</u><u> </u><u>.</u>

7 0
3 years ago
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