What is the domain of the absolute value function below?
2 answers:
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The value of g^-1(-3) is the value of x that makes g(x) = -3. To find it, we can solve
.. (x +4)/(2x -5) = -3
.. x +4 = -3(2x -5)
.. 7x = 11
.. x = 11/7
The desired value is
.. (3/11)*g^-1(-3)
.. = (3/11)*(11/7)
.. = 3/7
.. (x +4)/(2x -5) = -3
.. x +4 = -3(2x -5)
.. 7x = 11
.. x = 11/7
The desired value is
.. (3/11)*g^-1(-3)
.. = (3/11)*(11/7)
.. = 3/7
Answer:
48
Step-by-step explanation:
is basically the horizontal axis.
First, find the integral of x^2-25.
Remember that
integral of a constant is that constant times x.
Also that
to take the integral of a power function, add 1 to the degree and divide by that same degree.
We then get
Evaluate at -3
Then we evaluate at 0
Next, we subtract the the answer then we get
Answer:
because It's rounded to the nearest hundred place
Step-by-step explanation:
Given equation:
recall that,
remember, <em>In </em>is natural logarithm which is actually nothing but common logarithm with the base euler's number (<em>e)</em><em> </em>. anyway rewriting lnx=-3 yields:
1/e³ is approximately 0.0497870684..... , rounding it to the nearest hundred place would be 0.05 which is the same answer as your textbook .