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Annette [7]
4 years ago
15

What is the domain of the absolute value function below?

Mathematics
2 answers:
Anton [14]4 years ago
8 0
No info was given, plz post a pic of the equation
VARVARA [1.3K]4 years ago
4 0

Answer:

domain is all real numbers. (-infinity, infinity)

You can put any real number x value into the function.

Step-by-step explanation:

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3 years ago
Find the area bounded by the given curves: <br> y=2x−x2,y=2x−4
Andrej [43]

Answer:

A = [\frac{32}{3}]

Step-by-step explanation:

Given

y_1 = 2x - x^2

y_2 = 2x - 4

Required

Determine the area bounded by the curves

First, we need to determine their points of intersection

2x - x^2 = 2x - 4

Subtract 2x from both sides

-x^2 = -4

Multiply through by -1

x^2 = 4

Take square root of both sides

x = 2   or    x = -2

This Area is then calculated as thus

A = \int\limits^a_b {[y_1 - y_2]} \, dx

<em>Where a = 2 and b = -2</em>

Substitute values for y_1 and y_2

A = \int\limits^a_b {(2x - x^2) - (2x - 4)} \, dx

Open Brackets

A = \int\limits^a_b {2x - x^2 - 2x + 4} \, dx

Collect Like Terms

A = \int\limits^a_b {2x - 2x- x^2  + 4} \, dx

A = \int\limits^a_b {- x^2  + 4} \, dx

Integrate

A = [-\frac{x^{3}}{3} +4x](2,-2)

A = [-\frac{2^{3}}{3} +4(2)] - [-\frac{-2^{3}}{3} +4(-2)]

A = [-\frac{8}{3} +8] - [-\frac{-8}{3} -8]

A = [\frac{-8+ 24}{3}] - [\frac{8}{3} -8]

A = [\frac{-8+ 24}{3}] - [\frac{8-24}{3}]

A = [\frac{16}{3}] - [\frac{-16}{3}]

A = [\frac{16}{3}] + [\frac{16}{3}]

A = [\frac{16 + 16}{3}]

A = [\frac{32}{3}]

Hence, the Area is:

A = [\frac{32}{3}]

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Answer:

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Step-by-step explanation: This may help

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Answer:

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Step-by-step explanation:

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