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Anna007 [38]
3 years ago
8

Sylvia has 51.78 pounds of dirt. She has 20 buckets and would like to put 2.56 pounds of dirt into each bucket. Are there enough

buckets for all of the dirt to be in a bucket?
Mathematics
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

There isn't enough buckets for all of the dirt to be in a bucket.

Step-by-step explanation:

From the question,

She has 20 buckets and would like to put 2.56 pounds of dirt into each bucket.

Hence, the total number of dirt that can be in the 20 buckets is

20 × 2.56

= 51.20 pounds of dirt

Slyvia has 51.76 pounds of dirt.

51.76 - 51.20

= 0.56 pounds of dirt.

From the above calculation we can say that there isn't enough buckets for all of the dirt to be in a bucket

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Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
rusak2 [61]

Answer:

(a) The probability that the thickness is less than 3.0 mm is 0.119.

(b) The probability that the thickness is more than 7.0 mm is 0.119.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is 0.762.

Step-by-step explanation:

We are given that thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.0 millimeters (mm) and a standard deviation of 1.7 mm.

Let X = <u><em>thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village.</em></u>

So, X ~ Normal(\mu=5.0,\sigma^{2} =1.7^{2})

The z-score probability distribution for the normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean thickness = 5.0 mm

           \sigma = standard deviation = 1.7 mm

(a) The probability that the thickness is less than 3.0 mm is given by = P(X < 3.0 mm)

    P(X < 3.0 mm) = P( \frac{X-\mu}{\sigma} < \frac{3.0-5.0}{1.7} ) = P(Z < -1.18) = 1 - P(Z \leq 1.18)

                                                           = 1 - 0.8810 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(b) The probability that the thickness is more than 7.0 mm is given by = P(X > 7.0 mm)

    P(X > 7.0 mm) = P( \frac{X-\mu}{\sigma} > \frac{7.0-5.0}{1.7} ) = P(Z > 1.18) = 1 - P(Z \leq 1.18)

                                                           = 1 - 0.8810 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is given by = P(3.0 mm < X < 7.0 mm) = P(X < 7.0 mm) - P(X \leq 3.0 mm)

    P(X < 7.0 mm) = P( \frac{X-\mu}{\sigma} < \frac{7.0-5.0}{1.7} ) = P(Z < 1.18) = 0.881

    P(X \leq 3.0 mm) = P( \frac{X-\mu}{\sigma} \leq \frac{3.0-5.0}{1.7} ) = P(Z \leq -1.18) = 1 - P(Z < 1.18)

                                                           = 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

Therefore, P(3.0 mm < X < 7.0 mm) = 0.881 - 0.119 = 0.762.

4 0
4 years ago
Question help on this problem! Please
Ostrovityanka [42]

Answer:

Step-by-step explanation:

hi: the second, the third and the last one are true

5 0
3 years ago
Read 2 more answers
Please please help me
zhuklara [117]

Answer:

first one

Step-by-step explanation:

yes, the interval does increase at -2. however, you can see it decreases again but starts rising up again at the interval 1.

3 0
4 years ago
Find the following when a = -3, b = 6, c = −4/5 9b−72a+1
Vadim26 [7]
271.

Hope this helped!
8 0
3 years ago
I really need help asap please
gizmo_the_mogwai [7]
We can use the substitution method to solve this problem.

The second equation is \sf y=2x, so we can plug in 2x for 'y' in the first equation:

\sf 5x-2y=3

\sf 5x-2(2x)=3

Multiply:

\sf 5x-4x=3

Combine like terms:

\sf x=3

This is the x-value of our solution, we can plug this into any of the two equations to find the y-value:

\sf y=2x

\sf y=2(3)

Multiply:

\sf y=6

This is the y-value of our solution. So our entire solution is (3, 6).
5 0
3 years ago
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