Please answer ASAP! Plz I’m begging I really need this correct or my mum will be very very mad

Karin wants to use the distributive property to find the value of 19·42+19·58 mentally. Which expression can she use?

katrin2010 [14]

19 * 42 + 19 * 58 =
19(42 + 58) =
19 * 100 =
1900

7 0

4 years ago

Write two numbers that multiply to the value on top and add to the value on bottom. 27 -12

mariarad [96]

Multiply 3x9 and it gives u 27
And -3 plus -9 equal -12

4 0

3 years ago

Read 2 more answers

Which of the following is a correct conversion of 50 kg

wariber [46]

Answer:

c. 50kg = 50,000g

Step-by-step explanation:

We have to solve these following rule of three to see which of the following is a correct conversion of 50kg.

a)

Each kg has 1000g

So

1kg - 1000g

50kg - xg

x = 50*1000

x = 50,000g

Conversion a) is wrong

b)

Each kg has 1000000mg

So

1kg - 1000000g

50kg - x mg

x = 50*1000000

x = 50,000,000 mg

Conversion b) is wrong

c)

In a), we have already converted 50kg to g. We have verified that 50kg = 50,000g. So c. is correct

d)

In b), we have already converrted 50kg to mg. We have verified that 50kg = 50,000,000g. So d. is wrong

4 0

3 years ago

If a 10 symbol sequence is sent through the channel,what is the probability that up to 3 symbols are in error out of the 10trans

lina2011 [118]

Answer: 0.171887

Step-by-step explanation:

Given that S0 and S1 are binary symbol of equal probabilty;

P(S0) = P(S1) = 0.5

This probability is a Binomial random variable of sequence Sn, where Sn counting the number of success in a repeated trials.

P(Sn =X) = nCx p^x (1-p)^(n-1)

Pr(at most 3) = P(0<= x <=3) = P(X=0) + 0) + P(X=1) + P(X=2) + P(X=3)

Since there are only 2 values that occur in sequence 0 and 1 ( or S0 and S1).Let the distribution be given by the sequence (0111111111),(1011111111),(11011111111),...(1111111110) for Sn= 1 is the sequence for 1 error.

10C0, 10C1, 10C2, and 10C3 is the number of sequences in value for X= 0, 1, 2, 3 having value 0 and others are 1. Let the success be p(S0)=0.5 and p(S1)= 0.5

P(0<= X <=3) = 10C0 × (0.5)^0 × (0.5)^10 + 10C1× (0.5)¹ × (0.5)^9 + 10C2 × (0.5)² × (0.5)^8 + 10C3(0.5)³(0.5)^7

= 1 × (0.5)^10 + 10 × (0.5)^10 + 45 × (0.5)^10 + 120 × (0.5)^10

=0.000977 + 0.00977 + 0.04395 + 0.11719

= 0.171887

3 0

3 years ago

Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu

Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que