The pre-image point B(-4, 3) is translated to B'(-1, 1). What was the translation used?

I need help please?!!!!!!!

Rina8888 [55]

Answer:

The answer is A...

Step-by-step explanation:

Brainliest?

3 0

3 years ago

Read 2 more answers

A coordinate grid is placed over a college Station map. Tiger Stadium is located at (-3,2)

Olin [163]

Answer:

$4.61\ units$

Step-by-step explanation:

The complete question is

A coordinate grid is placed over a College Station map. Tiger Stadium is located at (-3, 2) and Kyle Field is located at (4, 8). If a shuttle bus stop is at the midpoint between Tiger Field and Kyle Field, which is the closest to the distance in coordinate units from Tiger Field to the shuttle bus stop?

Options

4.61 units

6.52 units

9.22 units

21.25 units

step 1

Find the midpoint between Tiger Field and Kyle Field ( shuttle bus stop)

we know that

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have the points

(-3, 2) and (4, 8)

substitute in the formula

$M=(\frac{-3+4}{2},\frac{2+8}{2})$

$M=(0.5,5)$

step 2

Find the distance from Tiger Field to the shuttle bus stop

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

(-3,2) and (0.5,5)

substitute in the formula

$d=\sqrt{(5-2)^{2}+(0.5+3)^{2}}$

$d=\sqrt{(3)^{2}+(3.5)^{2}}$

$d=\sqrt{21.25}\ units$

$d=4.61\ units$

6 0

3 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$