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cupoosta [38]
2 years ago
9

Factoriseb^3−b^2+b−1,2b^3−b^2+b−2​

Mathematics
1 answer:
Alex Ar [27]2 years ago
6 0

Answer:

(b² + 1) (b - 1)

Step-by-step explanation:

= b³ - b² + b - 1

= b² (b - 1) + 1(b - 1)

= (b² + 1) (b - 1)

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The table shows the highs and lows in temperature over the last week in two towns in separate states. Which matrix shows the dif
Bezzdna [24]

Answer:

  see attachment

Step-by-step explanation:

If we assume that the matrix is populated with (difference of high temperatures) in the first row and (difference of low temperatures) in the second row, we only need to look for one value.

The difference between the Monday high temperatures is 35 - 26 = 9 degrees. We expect that to be in the first row of the first column of the matrix we're looking for. We find that matrix in selection D.

8 0
2 years ago
If (1)=0, what are all the roots of the function f(x)=x3+3x2-x-3?use the remainder theorem
Anon25 [30]
If f(1)=0, then by the remainder theorem \dfrac{f(x)}{x-1} has a remainder of 0, which means f(x) is divisible by x-1. In fact,

x^3+3x^2-x-3=x^2(x+3)-(x+3)=(x^2-1)(x+3)=(x-1)(x+1)(x+3)

So we know 1 is a root, and the other two roots are -1 and -3.
6 0
3 years ago
280 is 72% of what number?
IgorLugansk [536]

Answer:

389

Step-by-step explanation:

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5 0
2 years ago
Write an equation of a line containing (2, 1) and (3, 4) in point-slope form.
ivann1987 [24]

Answer:

y-1=3(x-2)

Or

y-4=3(x-3)

Step-by-step explanation:

The slope formula is given by:

m=\frac{y_2-y_1}{x_2-x_1}

The line containing (2, 1) and (3, 4)  has slope;

m=\frac{4-1}{3-2}=3

The point-slope form is given by:

y-y_1=m(x-x_1)

We substitute the point and slope to get:

y-1=3(x-2)

Or

y-4=3(x-3)

8 0
3 years ago
A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the
Lelu [443]

Answer:

95% Confidence interval: (0.375,0.377)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 0.376 cc/cubic meter

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.0012

Degree of freedom =

=n-1\\=15-1\\=14

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.145  

0.376 \pm 2.145(\dfrac{0.0012}{\sqrt{15}} )\\\\ = 0.376 \pm 0.0006\\\\ = (0.3754,0.3766)\approx (0.375,0.377)  

(0.375,0.377) is the required 95% confidence interval for the population mean potassium chloride concentration.

5 0
3 years ago
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