Alright, so the number is less than 5, we pick it twice, and the sum (2*number) is less than 5, we have 2 options - 2 or 1. 3 or more doesn't work because 3*2=6. The probability of choosing 2 is 1/9, and choosing 2 again is 1/9. Since they don't have anything to do with each other, we multiply 1/9 by 1/9 to get 1/81 as the chance of choosing 2 twice. Since we can have 1 twice too, we add 1/81 to 1/81 to get 2/81
Answer : 25/51
The probability of drawing two red cards without replacement is 25/102 , and the probability of drawing one red card is 1/2 .
probability(drawing a second red card, given that the first card is red)
= Probability (drawing two red cards without replacement) divide by probability (drawing a one red card)
probability(drawing a second red card, given that the first card is red)
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Can you show the options ? It’ll make it easier to answer
The first one is b
the second one is a
the third one is c