Answer:
Step-by-step explanation:
Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
Answer:the answer is A my friend ;)
Step-by-step explanation:
Answer:
1130.97 (last option)
Step-by-step explanation:
Basically its the circumference times 12. Circumference of the circle is 2 * 15 * pi which is 30 pi. 30pi * 12 is 360pi which is around 1130.97 or the last option
Given:
S1 = 6 m
S2 = 8 m
S3 = 10 m
h = 3 m
Lateral Area Formula :
LA = hP ; height * perimeter
= 3m * (6 + 8 + 10)
= 3m * 24
LA = 72 m²
Surface Area Formula:
SA = 2B + hP : B = area of the base = ab / 2 = (6m * 8m)/2 = 48/2 = 24m²
SA = 2(24m²) + 72m²
SA = 48 m² + 72 m²
SA = 120 m²