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Art [367]
3 years ago
15

Given that v = (5,-4, 4) and w = (9-2,7) , evaluate v • w.

Mathematics
1 answer:
yuradex [85]3 years ago
4 0

Answer:

a

Step-by-step explanation:

Given

u = (x₁, y₁, z₁ ) and v = (x₂, y₂, z₂ ) then the dot product is

u • v = (x₁ x₂ ) + (y₁ y₂ ) + (z₁ z₂ )

Then

v • w

= (5 × 9) + (- 4 × - 2) + (4 × 7)

= 45 + 8 + 28

= 81 → a

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X y
Vanyuwa [196]

Answer:

a = 19

Step-by-step explanation:

If the rate of change is -8, subtract 8 from your y value of 27. And if 19 is correct, you should be able to subtract 8, and get 11 as the next number in the function, which you do, so 19 is the value of a.

5 0
3 years ago
Urgent help needed...............
andreyandreev [35.5K]

Answer:

Option b is correct

\{x | x \neq \pm 7, x\neq 0\}.

Step-by-step explanation:

Domain is the set of all possible values of x where function is defined.

Given the function:

h(x) = \frac{9x}{x(x^2-49)}

To find the domain of the given function:

Exclude the values of x, for which function is not defined

Set denominator = 0

x(x^2-49) = 0

By zero product property;

x = 0 and x^2-49= 0

⇒x = 0 and  x^2 =49

⇒x = 0 and x = \pm 7

Therefore, the domain of the given function is:

\{x | x \neq \pm 7, x\neq 0\}

7 0
3 years ago
Read 2 more answers
A bean salad has 20 beans in all. It is made up of:
vlabodo [156]
10 Lima beens
8 red beans
2 black-eyed beans
3 0
2 years ago
Use trigonometric identities to solve the trigonometric equation sin(2∅)-cos(∅)=0 for 0≤∅≤2π. You must show all of your work ana
SOVA2 [1]

Step-by-step explanation:

sin(2x) = 2sin(x)cos(x)

2sin(x)cos(x) - cos(x) = 0

so one solution is cos(x) = 0.

=> x = pi/2 and 3pi/2 (90° and 270°)

for cos(x) <> 0 we have then

2sin(x) - 1 = 0

2sin(x) = 1

sin(x) = 1/2

=> x = pi/6 and 5pi/6 (30° and 150°)

3 0
2 years ago
A large concrete water pipe is being laid underground. The pipe has a diameter of 24 inches and is laid in 40 foot sections. How
Dvinal [7]
Volume=hpir^2
d/2=r, 24/2=12=r
h=40

v=40pi12²
v=40pi144
v=5760pi cubic inches per section
5 0
3 years ago
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