A balanced coin will have 50:50 chance of showing either head or tail. In this question, you are asked the probability to find the first head after two tosses. That means the toss result should be:
1. tail = 1/2 probability
2. head = 1/2 probability
Previously you are tossing the coin 10 times and obtain zero head. But this previous 10 tosses result should not influence your probability in the 11th and 12th toss. The chance will always be 50:50 no matter how much the tosses count. So the probability should be: 1/2 * 1/2= 1/4
Answer: -8/4
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given</u>
- Q(s) = -4s^3 + 7s^2 - 24;
- s = -4 and 1
<u>Verifying zeroes</u>
Q(-4) =
- -4(-4)^3 + 7(-4)^2 - 24 =
- 256 + 112 - 24 =
- 344
- Incorrect as 344 ≠ 0
Q(1) =
- -4(1)^3 + 7(1)^2 - 24 =
- -12 + 7 - 24 =
- -29
- Incorrect as -29 ≠ 0
$7.50(2)=$15.00 (She takes the taxi twice, and its $7.50 each time she takes it)
$0.45(16)+$0.45(8)=$10.80 (Each mile is $0.45, she goes 16 miles on the way to work, and only 8 miles on the way home. Since she walks half way and takes the taxi the other half. Half of 16 is 8)
$15.00+$10.80=$25.80
Alexis pays $25.00 per day for her taxi rides.
The answer to this problem is the letter "A" which is "Multiply by 3, then add 2"
and can be written a N = 3n + 2
At first, we have initial value such n = 1
Then the second value is:
N = 3*1 + 2
N = 5
The third value is:
N = 3*5 + 2
N=17
The next values are:
N = 3*17 + 2
N= 53
The letter "A" is the inductive reasoning to the given sequence.
