Option C:
The rate of change is $3 per picture.
Solution:
<em>Rate of change is same as the slope of the line.</em>
Take any two points on the graph.
(0, 20) and (20, 80) are two points on the line of the graph.
![x_1=0, y_1=20, x_2=20, y_2=80](https://tex.z-dn.net/?f=x_1%3D0%2C%20y_1%3D20%2C%20x_2%3D20%2C%20y_2%3D80)
Slope of two points formula:
![$m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![$m=\frac{80-20}{20-0}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7B80-20%7D%7B20-0%7D)
![$m=\frac{60}{20}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7B60%7D%7B20%7D)
![$m=\frac{3}{1}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7B3%7D%7B1%7D)
m = 3
The rate of change is $3 per picture.
Hence option C is the correct answer.
Answer:
iguoblb 55
Step-by-step explanation:
43/10 - 12/5x + 11/2 = 1/2(-18/5x + 6/5)
Do the stuff in parentheses first
43/10 - 12/5x + 11/2 = -9/5x + 3/5
Now we have to isolate the everything with an x in ine side, and the stuff without x (the variable) on the other
Do this by adding 12/5x to both sides of the equation to switch the -12/5x to the right side
43/10 - 12/5x + 12/5x + 11/2= -9/5x + 3/5 + 12/5x
43/10 + 11/2 = -9/5x + 3/5 + 12/5x
98/10 = 3/5x + 3/5
Now subtract both sides by 3/5 to switch the 3/5 to the left side
98/10 - 3/5 = 3/5x + 3/5 - 3/5
98/10 - 6/10 = 3/5x
3/5x = 92/10
Now divide both sides by 3/5
3/5x÷3/5 = 92/10 ÷ 3/5
x = (92×5)/(10×3)
x = 92/6
hope it helps, I double checked, it is correct.
just let me know uf you have any questions :)
Answer:
1. fraction is 64/100 and decimal is 0.64
2. 12.5 is percent, decimal is 0.125
3. 140 is percent, I think is 1 2/5
4. 2.75 is decimal, 275 as percent
5. 0.08 is decimal, I think is 16/25
Answer:
D
Step-by-step explanation: