Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer: I don’t actually know sorry
Step-by-step explanation:
Answer:
Answer D
Step-by-step explanation:
Answer:$344
1/5 of 400 is 80 so if you subtract that it would be $320
1/50 of $400 is 8 so if you multiply that by 3,3/50 of $400 is(8*3)24 so $320+$24=$344
The way to get the equation for the radius (r) is to get r by itself. So divide each side by 4pi
500/4pi=r^2
Now take the square root of each side to get the equation of r.
sqrt(500/4pi)=r