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KiRa [710]
1 year ago
14

The image of the point (3, -4) under a translation is (0, –5). Find the coordinatesof the image of the point (8,7) under the sam

e translation.

Mathematics
1 answer:
Sav [38]1 year ago
6 0

We will have the following:

*First: We determine the translation rule:

We have that the point went from (3, -4) to (0, -5), thus the translation rule would be:

(x,y)\to(x-3,x-1)

Second: We apply the translation rule to the other point to determine it's image, that is:

(8,7)\to(8-3,7-1)\to(5,6)

So, the image of the second point is (5, 6).

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How to graph the function f(x)=-2(x+3) +4
Paraphin [41]

Answer:

Step-by-step explanation:

first of all, simplify your fraction. f(x)= -2(x+3) + 4

                                                     f(x)= (-2x-6) + 4

                                                     f(x)= -2x-2

y intercept is -2 and the slope is -2, go down 2 and right 1

3 0
3 years ago
What percent of 130 is 182
Greeley [361]
The answer is 140 percent
6 0
3 years ago
ANSWER QUICK PLEASE
scoundrel [369]

Answer:

23 1/4

Step-by-step explanation:

8 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
Convert 6 4/5 to an improper fraction
dsp73
6+(4/5)

=(30/5)+(4/5)

=34/5
5 0
3 years ago
Read 2 more answers
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