Y = sin x
y' = cos x
y'' = -sin x
y''' = -cos x
y'''' = sin x
Therefore, nth derivative of sin x = sin(nπ/2 + x)
Answer:
13
Step-by-step explanation:
3y+2x=13
2y+3x=0
∴3y+2x+2y+3x=13+0
∴3y+2y+2x+3x=13
∴5y+5x=13
Hope this helps you mate!
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Answer:
16 (units)
Step-by-step explanation:
3.2<em>n</em>
<em>n</em> is a variable, so when you <em>let n = 5, </em>you substitute.
3.2<em>n</em> = 3.2 * 5 = 16 (units)
The tensile strength of spider silk is about 1150 MPa, which is 1.15 x 10^9 N/m².
<span>So given that the diameter of the spider silk is 0.15 mm or 1.5 x 10^-4 m. The cross sectional area is approximately: </span>
<span>A = πr² = (3.14)(1.5 x 10^-4 / 2)² = 1.767 x 10^-8 m² </span>
<span>So this means that the amount of force we can apply before the the silk thread is broken is: </span>
<span>F = PA = (1.15 x 10^9)(1.767 x 10^-8) = 20.32 N </span>
<span>F = mg, so m = F/g = (20.32)/(9.81) = 2.07 kg!!! </span>
