All categories

3 years ago

What is the volume, in cubic cm, of a cylinder with a height of 16cm and a base radius of 3cm, to the nearest tenths place?

Mathematics

2 answers:

Lelechka [254]3 years ago

6 0

V = π r^2 h

= 3.14 * 3^2 * 16

= 3.14 * 9 * 16

= 452.16

charle [14.2K]3 years ago

3 0

Answer:452

Step-by-step explanation:

You might be interested in

Quadrilateral abcd has the vertices a(-6,4) , b(-4,5) , c(-3,3) , d(-5,1) . determine if quadrilateral abcd is a rhombus

bazaltina [42]

Answer:

Step-by-step explanation:

The defining property of a rhombus is that it has equal side lengths.

=============================================================

Finding all side lengths :

AB

⇒ √(-4 + 6)² + (5 - 4)²

⇒ √2² + 1²

⇒ √5 units

BC

⇒ √(-3 + 4)² + (3 - 5)²

⇒ √1² + (-2)²

⇒ √5 units

CD

⇒ √(-5 + 3)² + (1 - 3)²

⇒ √(-2)² + (-2)²

⇒ √8 units

DA

⇒ √(-6 + 5)² + (4 - 1)²

⇒ √(-1)² + 3²

⇒ √10 units

As all side lengths of the quadrilateral are not equal, ABCD is not a rhombus.

3 0

2 years ago

Find the geometric mean of the pair numbers 6 and 10

inn [45]

Answer:

The geometric mean between 6 and 10 will be:

$G.M=2\sqrt{15}$

Step-by-step explanation:

We know that the geometric mean between the two numbers 'a' and 'b' is defined as:

$G.M=\sqrt{a\times b}$

Now, let us determine the geometric mean between 6 and 10

a = 6

b = 10

Using the formula

$G.M=\sqrt{a\times b}$

$G.M=\sqrt{6\times 10}$

$=\sqrt{60}$

$=\:\sqrt{4\times 15}$

$=2\sqrt{15}$

Therefore, the geometric mean between 6 and 10 will be:

$G.M=2\sqrt{15}$

3 0

2 years ago

Algebra question: Anita rides her bike 82.4 miles each month. Which is the best estimate of the total distance Anita bikes in 6

alekssr [168]

*(Answer)*= $494.4$

4 0

3 years ago

Read 2 more answers

The car travels an average of 40km per litre of fuel, and the cost of fuel is £1.25 per litre. Calculate the cost of the fuel fo

Nuetrik [128]

$31075 \div 40 = 776.875 \\ 776.875 \times 1.25 = 971.09375$
The cost of fuel was £971.09

5 0

3 years ago

In ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. Find the measure of ∠J to the nearest degree.

nydimaria [60]

We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.

First of all, we will draw a triangle as shown in the attachment.

We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.

We know that sine relates opposite side of right triangle to hypotenuse.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(\angle J)=\frac{22}{54}$

Using inverse sine or arcsin, we will get:

$\angle J=\text{sin}^{-1}(\frac{22}{54})$

$\angle J=24.042075905756^{\circ}$

Upon rounding to nearest degree, we will get:

$\angle J\approx 24^{\circ}$

Therefore, the measure of angle J is approximately 24 degrees.

8 0

3 years ago