3 years ago

What is 1,345/99 rounded to the nearest integer?

Mathematics

1 answer:

arlik [135]3 years ago

6 0

$\frac{1345}{99} \approx 13.58 \approx \boxed{\bf{14}}$

You might be interested in

PLEASE HELP! I AM NEED IT DESPERATELY!! Write the equation of the line in point-slope form.

Pie

Answer:

y= -2x/3+8

Step-by-step explanation:

find 2 points: (0,8) and (6,4)

substitute in y=ax+b

8=0a+b

b=8

4=6a+b

4=6a+8

6a=-4

a=-2/3

8 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Polygon ABCD has sides with these lengths: , 5 units; , 4 units; , 4.5 units;

Airida [17]

Answer:

5 units

Step-by-step explanation:

5 0

2 years ago

25° decreased by 60%

worty [1.4K]

25 - (60% × 25) =
25 - 60% × 25 =
(1 - 60%) × 25 =
(100% - 60%) × 25 =
40% × 25 =
40 ÷ 100 × 25 =
40 × 25 ÷ 100 =
1,000 ÷ 100 =
10;
The answer is 10

4 0

3 years ago

Assume that trees are subjected to different levels of carbon dioxide atmosphere with 7% of the trees in a minimal growth condit

taurus [48]

Answer: The mean and standard deviation are 567.2 and 89.88 resp.

Step-by-step explanation:

Since we have given that

For 370 parts per million = 7% = 0.07

For 440 parts per million = 10% = 0.10

For 550 parts per million = 49% = 0.49

For 670 parts per million = 34% = 0.34

So, Mean of the carbon dioxide atmosphere for these trees would be

$E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2$

And

$E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794$

So, Variance would be

$Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16$

So, the standard deviation would be

$\sigma=\sqrt{8078.16}=89.88$

Hence, the mean and standard deviation are 567.2 and 89.88 resp.

3 0

3 years ago

(SAT Prep) Find the value of x.

photoshop1234 [79]

Answer:

Step-by-step explanation:

I think

6 0

3 years ago

Read 2 more answers