Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
Answer:hope you like it
Step-by-step explanation:basic pencil and a4 sheet of paper
Law of cosines:
a^2 = b^2 + c^2 -2 *b*c*coa(a)
a^2 = 60.5^2 + 257^2 - 2*60.5*257*cos(31)
a^2 = 3660.25 + 66049 - 2 *60.5 * 257 * 0.857167
a^2 = 3660.25 + 66049 - 26655.33
a^2 = 43053.92
a = SQRT(43053.92)
a = 207.49 = 207.5 feet.
The answer is A.