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3 years ago

Quick help...........

Mathematics

2 answers:

Doss [256]3 years ago

7 0

Answer:

The fries cost 2 dollars and the onion rings cost 3

Step-by-step explanation:

For the first question, we know that together, they equal 5 dollars. I assume that these will be divided to be one of the dishes costing 3 and the other costing two. I then plug these in with the numbers of the dishes ordered and see what fits with the final cost.

ozzi3 years ago

4 0

Answer:

fries are $2 onion rings $3

Step-by-step explanation:

say fries are y and onion rings are X we get two simultaneous equations

y+x= 5 and 3y+2x=12

equal either X or y, I will do x

2y+2x=10 and 3y+2x=12

take the first equation fromm the second

y=2

them sub y into one of the original equations to solve X,

y+x=5

2+X=5

x=3

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Which value can be added to the set below without changing its mean?

shusha [124]

Answer:

15..

Step-by-step explanation:

4, 10, 14, 18, 22, 22

Mean = (4 + 10 + 14 + 18 + 22 + 22)/6

= 90/6

= 15.

Number to be added, 'y'

For the mean to be the same

(90 + y) / 7 = 15

90 + y = 15 × 7

90 + y = 105

y = 105 - 90

= 15

7 0

3 years ago

What is the inverse of y=r? + 8?

Maru [420]

Answer:

F-1(x)=x+8

Step-by-step explanation:

What is the inverse of y=r? + 8?

I hope this help.

6 0

3 years ago

Solve y=x+8 for x<br> can some one help me with this problem

IRINA_888 [86]

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7 0

3 years ago

PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

3 0

3 years ago

Mariana walked 3/10 mile to the park. Later, she walked 1/4 mile to a friend's house. Then she walked 2/5 mile home. How many mi

Paladinen [302]

Answer:

19/20 of a mile.

Step-by-step explanation:

$\frac{3}{10} + \frac{1}{4} + \frac{2}{5}$

The common denominator is 20 so we times the first one by 2 the second one by 5 and the last one by 4. (Both numerator and denominator.)

You will end up with this $\frac{6}{20} + \frac{5}{20} + \frac{8}{20} = \frac{19}{20}$

7 0

3 years ago